Skip to main content

125. Valid Palindrome

Description

A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers.

Given a string s, return true if it is a palindrome, or false otherwise.

참고

You can read the full description here.

Solution

Approach

  1. Filter characters. Remove characters except for alphabets or numbers.
    1. re.sub is a good choice.
  2. Compare strings or lists.

Implementation

class Solution:
def isPalindrome(self, s: str) -> bool:
res = []
# O(N)
for letter in s:
if (letter.isalnum()):
res.append(letter.lower())

# Slicing is O(1), list comparision is O(N)
return res == res[::-1]

Complexity Analysis

  • nn : number of characters in sentence s )
  • Time Complexity : O(n)O(n)
  • Space Complexit : O(n)O(n)